(x+8)(x-7)(x2-2x+5)=0

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Solution for (x+8)(x-7)(x2-2x+5)=0 equation: 



(x+8)(x-7)(x2-2x+5)=0

We add all the numbers together, and all the variables

(x+8)(x-7)(+x^2-2x+5)=0

We multiply parentheses ..

(+x^2-7x+8x-56)(+x^2-2x+5)=0

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