(x+8)2=x2+x+

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Solution for (x+8)2=x2+x+ equation:



(x+8)2=x2+x+
We move all terms to the left:
(x+8)2-(x2+x+)=0
We add all the numbers together, and all the variables
-(+x^2+x+)+(x+8)2=0
We multiply parentheses
-(+x^2+x+)+2x+16=0
We get rid of parentheses
-x^2-x+2x+16-=0
We add all the numbers together, and all the variables
-1x^2+x=0
a = -1; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-1)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-1}=\frac{-2}{-2} =1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-1}=\frac{0}{-2} =0 $

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