(x+8)2=x2+x+

Solution for (x+8)2=x2+x+ equation:

(x+8)2=x2+x+

We move all terms to the left:

(x+8)2-(x2+x+)=0

We add all the numbers together, and all the variables

-(+x^2+x+)+(x+8)2=0

We multiply parentheses

-(+x^2+x+)+2x+16=0

We get rid of parentheses

-x^2-x+2x+16-=0

We add all the numbers together, and all the variables

-1x^2+x=0

a = -1; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-1)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-1}=\frac{-2}{-2}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-1}=\frac{0}{-2}
=0
$