(x+8)=(9x+100)/10

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Solution for (x+8)=(9x+100)/10 equation: 



(x+8)=(9x+100)/10

We move all terms to the left:

(x+8)-((9x+100)/10)=0

We get rid of parentheses

x-((9x+100)/10)+8=0

We multiply all the terms by the denominator


x*10)-((9x+100)+8*10)=0

We add all the numbers together, and all the variables

x*10)-((9x+100)=0

Wy multiply elements

10x^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$

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