(x+8)=(9x+100)/10

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Solution for (x+8)=(9x+100)/10 equation:



(x+8)=(9x+100)/10
We move all terms to the left:
(x+8)-((9x+100)/10)=0
We get rid of parentheses
x-((9x+100)/10)+8=0
We multiply all the terms by the denominator
x*10)-((9x+100)+8*10)=0
We add all the numbers together, and all the variables
x*10)-((9x+100)=0
Wy multiply elements
10x^2=0
a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$

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