(x+8/x+4)+3=(6x-12/x-4)

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Solution for (x+8/x+4)+3=(6x-12/x-4) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+8/x+3+4 = 6*x-(12/x)-4 // - 6*x-(12/x)-4

x-(6*x)+8/x+12/x+3+4+4 = 0

x-6*x+8/x+12/x+3+4+4 = 0

20*x^-1-5*x^1+11*x^0 = 0

(11*x^1-5*x^2+20*x^0)/(x^1) = 0 // * x^2

x^1*(11*x^1-5*x^2+20*x^0) = 0

x^1

11*x-5*x^2+20 = 0

11*x-5*x^2+20 = 0

DELTA = 11^2-(-5*4*20)

DELTA = 521

DELTA > 0

x = (521^(1/2)-11)/(-5*2) or x = (-521^(1/2)-11)/(-5*2)

x = (521^(1/2)-11)/(-10) or x = (521^(1/2)+11)/10

x in { (521^(1/2)-11)/(-10), (521^(1/2)+11)/10}

x in { (521^(1/2)-11)/(-10), (521^(1/2)+11)/10 }

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