(x+9)(x+7)=99

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Solution for (x+9)(x+7)=99 equation:



(x+9)(x+7)=99
We move all terms to the left:
(x+9)(x+7)-(99)=0
We multiply parentheses ..
(+x^2+7x+9x+63)-99=0
We get rid of parentheses
x^2+7x+9x+63-99=0
We add all the numbers together, and all the variables
x^2+16x-36=0
a = 1; b = 16; c = -36;
Δ = b2-4ac
Δ = 162-4·1·(-36)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-20}{2*1}=\frac{-36}{2} =-18 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+20}{2*1}=\frac{4}{2} =2 $

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