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(x+9)(x+8)+2x=2(x+8)+4(x+9)
We move all terms to the left:
(x+9)(x+8)+2x-(2(x+8)+4(x+9))=0
We add all the numbers together, and all the variables
2x+(x+9)(x+8)-(2(x+8)+4(x+9))=0
We multiply parentheses ..
(+x^2+8x+9x+72)+2x-(2(x+8)+4(x+9))=0
We calculate terms in parentheses: -(2(x+8)+4(x+9)), so:We get rid of parentheses
2(x+8)+4(x+9)
We multiply parentheses
2x+4x+16+36
We add all the numbers together, and all the variables
6x+52
Back to the equation:
-(6x+52)
x^2+8x+9x+2x-6x+72-52=0
We add all the numbers together, and all the variables
x^2+13x+20=0
a = 1; b = 13; c = +20;
Δ = b2-4ac
Δ = 132-4·1·20
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{89}}{2*1}=\frac{-13-\sqrt{89}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{89}}{2*1}=\frac{-13+\sqrt{89}}{2} $
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