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(x+9)(x-3)=(x+1)(x
We move all terms to the left:
(x+9)(x-3)-((x+1)(x)=0
We multiply parentheses ..
(+x^2-3x+9x-27)-((x+1)x=0
We get rid of parentheses
x^2-3x+9x-((x+1)x-27=0
We add all the numbers together, and all the variables
x^2+6x-((x+1)x-27=0
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