(x+9+x-5)x-5=36

Solution for (x+9+x-5)x-5=36 equation:

(x+9+x-5)x-5=36

We move all terms to the left:

(x+9+x-5)x-5-(36)=0

We add all the numbers together, and all the variables

(2x+4)x-5-36=0

We add all the numbers together, and all the variables

(2x+4)x-41=0

We multiply parentheses

2x^2+4x-41=0

a = 2; b = 4; c = -41;
Δ = b2-4ac
Δ = 42-4·2·(-41)
Δ = 344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{344}=\sqrt{4*86}=\sqrt{4}*\sqrt{86}=2\sqrt{86}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{86}}{2*2}=\frac{-4-2\sqrt{86}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{86}}{2*2}=\frac{-4+2\sqrt{86}}{4}
$