(x+iy)(1-2i)=5

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Solution for (x+iy)(1-2i)=5 equation: 


Simplifying
(x + iy)(1 + -2i) = 5

Reorder the terms:
(iy + x)(1 + -2i) = 5

Multiply (iy + x) * (1 + -2i)
(iy(1 + -2i) + x(1 + -2i)) = 5
((1 * iy + -2i * iy) + x(1 + -2i)) = 5
((1iy + -2i2y) + x(1 + -2i)) = 5
(1iy + -2i2y + (1 * x + -2i * x)) = 5

Reorder the terms:
(1iy + -2i2y + (-2ix + 1x)) = 5
(1iy + -2i2y + (-2ix + 1x)) = 5

Reorder the terms:
(-2ix + 1iy + -2i2y + 1x) = 5
(-2ix + 1iy + -2i2y + 1x) = 5

Solving
-2ix + 1iy + -2i2y + 1x = 5

Solving for variable 'i'.

Reorder the terms:
-5 + -2ix + 1iy + -2i2y + 1x = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + -2ix + 1iy + -2i2y + 1x = 0

The solution to this equation could not be determined.

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