(x+x,)+(x/2)+1=100

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Solution for (x+x,)+(x/2)+1=100 equation: 



(x+x.)+(x/2)+1=100

We move all terms to the left:

(x+x.)+(x/2)+1-(100)=0

We add all the numbers together, and all the variables

(+x+x.)+(+x/2)+1-100=0

We add all the numbers together, and all the variables

(+x+x.)+(+x/2)-99=0

We get rid of parentheses

x+x.+x/2-99=0

We multiply all the terms by the denominator


x*2+(x.)*2+x-99*2=0

We add all the numbers together, and all the variables

x*2+(+x.)*2+x-99*2=0

We add all the numbers together, and all the variables

x+x*2+(+x.)*2-198=0

We multiply parentheses

x+x*2+2x-198=0

Wy multiply elements

x+2x+2x-198=0

We add all the numbers together, and all the variables

5x-198=0

We move all terms containing x to the left, all other terms to the right

5x=198

x=198/5

x=39+3/5

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