(x+y)(n+1)-3(n+1)=

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Solution for (x+y)(n+1)-3(n+1)= equation:


Simplifying
(x + y)(n + 1) + -3(n + 1) = 0

Reorder the terms:
(x + y)(1 + n) + -3(n + 1) = 0

Multiply (x + y) * (1 + n)
(x(1 + n) + y(1 + n)) + -3(n + 1) = 0
((1 * x + n * x) + y(1 + n)) + -3(n + 1) = 0

Reorder the terms:
((nx + 1x) + y(1 + n)) + -3(n + 1) = 0
((nx + 1x) + y(1 + n)) + -3(n + 1) = 0
(nx + 1x + (1 * y + n * y)) + -3(n + 1) = 0

Reorder the terms:
(nx + 1x + (ny + 1y)) + -3(n + 1) = 0
(nx + 1x + (ny + 1y)) + -3(n + 1) = 0

Reorder the terms:
(nx + ny + 1x + 1y) + -3(n + 1) = 0
(nx + ny + 1x + 1y) + -3(n + 1) = 0

Reorder the terms:
nx + ny + 1x + 1y + -3(1 + n) = 0
nx + ny + 1x + 1y + (1 * -3 + n * -3) = 0
nx + ny + 1x + 1y + (-3 + -3n) = 0

Reorder the terms:
-3 + -3n + nx + ny + 1x + 1y = 0

Solving
-3 + -3n + nx + ny + 1x + 1y = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + -3n + nx + ny + 1x + 3 + 1y = 0 + 3

Reorder the terms:
-3 + 3 + -3n + nx + ny + 1x + 1y = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -3n + nx + ny + 1x + 1y = 0 + 3
-3n + nx + ny + 1x + 1y = 0 + 3

Combine like terms: 0 + 3 = 3
-3n + nx + ny + 1x + 1y = 3

Add '-1x' to each side of the equation.
-3n + nx + ny + 1x + -1x + 1y = 3 + -1x

Combine like terms: 1x + -1x = 0
-3n + nx + ny + 0 + 1y = 3 + -1x
-3n + nx + ny + 1y = 3 + -1x

Add '-1y' to each side of the equation.
-3n + nx + ny + 1y + -1y = 3 + -1x + -1y

Combine like terms: 1y + -1y = 0
-3n + nx + ny + 0 = 3 + -1x + -1y
-3n + nx + ny = 3 + -1x + -1y

Reorder the terms:
-3 + -3n + nx + ny + x + y = 3 + -1x + -1y + -3 + x + y

Reorder the terms:
-3 + -3n + nx + ny + x + y = 3 + -3 + -1x + x + -1y + y

Combine like terms: 3 + -3 = 0
-3 + -3n + nx + ny + x + y = 0 + -1x + x + -1y + y
-3 + -3n + nx + ny + x + y = -1x + x + -1y + y

Combine like terms: -1x + x = 0
-3 + -3n + nx + ny + x + y = 0 + -1y + y
-3 + -3n + nx + ny + x + y = -1y + y

Combine like terms: -1y + y = 0
-3 + -3n + nx + ny + x + y = 0

The solution to this equation could not be determined.

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