(x+y)+(y+z)+(x+z)=72

Solution for (x+y)+(y+z)+(x+z)=72 equation:

Simplifying
(x + y) + (y + z) + (x + z) = 72

Remove parenthesis around (x + y)
x + y + (y + z) + (x + z) = 72

Remove parenthesis around (y + z)
x + y + y + z + (x + z) = 72

Remove parenthesis around (x + z)
x + y + y + z + x + z = 72

Reorder the terms:
x + x + y + y + z + z = 72

Combine like terms: x + x = 2x
2x + y + y + z + z = 72

Combine like terms: y + y = 2y
2x + 2y + z + z = 72

Combine like terms: z + z = 2z
2x + 2y + 2z = 72

Solving
2x + 2y + 2z = 72

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y' to each side of the equation.
2x + 2y + -2y + 2z = 72 + -2y

Combine like terms: 2y + -2y = 0
2x + 0 + 2z = 72 + -2y
2x + 2z = 72 + -2y

Add '-2z' to each side of the equation.
2x + 2z + -2z = 72 + -2y + -2z

Combine like terms: 2z + -2z = 0
2x + 0 = 72 + -2y + -2z
2x = 72 + -2y + -2z

Divide each side by '2'.
x = 36 + -1y + -1z

Simplifying
x = 36 + -1y + -1z