(x+yi)(1+3i)=17+i

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Solution for (x+yi)(1+3i)=17+i equation: 


Simplifying
(x + yi)(1 + 3i) = 17 + i

Reorder the terms:
(iy + x)(1 + 3i) = 17 + i

Multiply (iy + x) * (1 + 3i)
(iy(1 + 3i) + x(1 + 3i)) = 17 + i
((1 * iy + 3i * iy) + x(1 + 3i)) = 17 + i
((1iy + 3i2y) + x(1 + 3i)) = 17 + i
(1iy + 3i2y + (1 * x + 3i * x)) = 17 + i

Reorder the terms:
(1iy + 3i2y + (3ix + 1x)) = 17 + i
(1iy + 3i2y + (3ix + 1x)) = 17 + i

Reorder the terms:
(3ix + 1iy + 3i2y + 1x) = 17 + i
(3ix + 1iy + 3i2y + 1x) = 17 + i

Solving
3ix + 1iy + 3i2y + 1x = 17 + i

Solving for variable 'i'.

Reorder the terms:
-17 + -1i + 3ix + 1iy + 3i2y + 1x = 17 + i + -17 + -1i

Reorder the terms:
-17 + -1i + 3ix + 1iy + 3i2y + 1x = 17 + -17 + i + -1i

Combine like terms: 17 + -17 = 0
-17 + -1i + 3ix + 1iy + 3i2y + 1x = 0 + i + -1i
-17 + -1i + 3ix + 1iy + 3i2y + 1x = i + -1i

Combine like terms: i + -1i = 0
-17 + -1i + 3ix + 1iy + 3i2y + 1x = 0

The solution to this equation could not be determined.

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