(x+yi)(2-3i)=-13i

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Solution for (x+yi)(2-3i)=-13i equation: 


Simplifying
(x + yi)(2 + -3i) = -13i

Reorder the terms:
(iy + x)(2 + -3i) = -13i

Multiply (iy + x) * (2 + -3i)
(iy(2 + -3i) + x(2 + -3i)) = -13i
((2 * iy + -3i * iy) + x(2 + -3i)) = -13i
((2iy + -3i2y) + x(2 + -3i)) = -13i
(2iy + -3i2y + (2 * x + -3i * x)) = -13i

Reorder the terms:
(2iy + -3i2y + (-3ix + 2x)) = -13i
(2iy + -3i2y + (-3ix + 2x)) = -13i

Reorder the terms:
(-3ix + 2iy + -3i2y + 2x) = -13i
(-3ix + 2iy + -3i2y + 2x) = -13i

Solving
-3ix + 2iy + -3i2y + 2x = -13i

Solving for variable 'i'.

Reorder the terms:
13i + -3ix + 2iy + -3i2y + 2x = -13i + 13i

Combine like terms: -13i + 13i = 0
13i + -3ix + 2iy + -3i2y + 2x = 0

The solution to this equation could not be determined.

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