(x-)(x-3)=12

Solution for (x-)(x-3)=12 equation:

(x-)(x-3)=12

We move all terms to the left:

(x-)(x-3)-(12)=0

We add all the numbers together, and all the variables

(+x)(x-3)-12=0

We multiply parentheses ..

(+x^2-3x)-12=0

We get rid of parentheses

x^2-3x-12=0

a = 1; b = -3; c = -12;
Δ = b2-4ac
Δ = -32-4·1·(-12)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{57}}{2*1}=\frac{3-\sqrt{57}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{57}}{2*1}=\frac{3+\sqrt{57}}{2}
$