(x-+2)(x+4)(x+6)(x+8)+16=0

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Solution for (x-+2)(x+4)(x+6)(x+8)+16=0 equation: 



(x-+2)(x+4)(x+6)(x+8)+16=0

We add all the numbers together, and all the variables

(+x)(x+4)(x+6)(x+8)+16=0

We multiply parentheses ..

(+x^2+4x)(x+6)(x+8)+16=0

We multiply parentheses ..

(+x^2+4x)(+x^2+8x+6x+48)+16=0

We move all terms containing x to the left, all other terms to the right

(+x^2+4x)(+x^2+8x+6x+48)=-16

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