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(x-1)(2x+3)=(x-1)(2x+1)
We move all terms to the left:
(x-1)(2x+3)-((x-1)(2x+1))=0
We multiply parentheses ..
(+2x^2+3x-2x-3)-((x-1)(2x+1))=0
We calculate terms in parentheses: -((x-1)(2x+1)), so:We get rid of parentheses
(x-1)(2x+1)
We multiply parentheses ..
(+2x^2+x-2x-1)
We get rid of parentheses
2x^2+x-2x-1
We add all the numbers together, and all the variables
2x^2-1x-1
Back to the equation:
-(2x^2-1x-1)
2x^2-2x^2+3x-2x+1x-3+1=0
We add all the numbers together, and all the variables
2x-2=0
We move all terms containing x to the left, all other terms to the right
2x=2
x=2/2
x=1
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