(x-1)(2x-3)=x

Solution for (x-1)(2x-3)=x equation:

(x-1)(2x-3)=x

We move all terms to the left:

(x-1)(2x-3)-(x)=0

We add all the numbers together, and all the variables

-1x+(x-1)(2x-3)=0

We multiply parentheses ..

(+2x^2-3x-2x+3)-1x=0

We get rid of parentheses

2x^2-3x-2x-1x+3=0

We add all the numbers together, and all the variables

2x^2-6x+3=0

a = 2; b = -6; c = +3;
Δ = b2-4ac
Δ = -62-4·2·3
Δ = 12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12}=\sqrt{4*3}=\sqrt{4}*\sqrt{3}=2\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{3}}{2*2}=\frac{6-2\sqrt{3}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{3}}{2*2}=\frac{6+2\sqrt{3}}{4}
$