(x-1)(x+1)-6-5x/3=(x+2)2

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Solution for (x-1)(x+1)-6-5x/3=(x+2)2 equation: 



(x-1)(x+1)-6-5x/3=(x+2)2

We move all terms to the left:

(x-1)(x+1)-6-5x/3-((x+2)2)=0

We use the square of the difference formula

x^2-5x/3-((x+2)2)-1-6=0

We multiply all the terms by the denominator


x^2*3-5x-(((x+2)2))*3-1*3-6*3=0

We add all the numbers together, and all the variables

x^2*3-5x-(((x+2)2))*3-21=0

Wy multiply elements

3x^2-5x-(((x+2)2))*3-21=0

We move all terms containing x to the left, all other terms to the right

3x^2-5x-(((x+2)2))*3=21

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