(x-1)(x+1)=(x+1)(x-5)

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Solution for (x-1)(x+1)=(x+1)(x-5) equation: 



(x-1)(x+1)=(x+1)(x-5)

We move all terms to the left:

(x-1)(x+1)-((x+1)(x-5))=0

We use the square of the difference formula

x^2-((x+1)(x-5))-1=0

We multiply parentheses ..

x^2-((+x^2-5x+x-5))-1=0



We calculate terms in parentheses: -((+x^2-5x+x-5)), so:

(+x^2-5x+x-5)

We get rid of parentheses

x^2-5x+x-5

We add all the numbers together, and all the variables

x^2-4x-5

Back to the equation:

-(x^2-4x-5)



We get rid of parentheses

x^2-x^2+4x+5-1=0

We add all the numbers together, and all the variables

4x+4=0

We move all terms containing x to the left, all other terms to the right

4x=-4

x=-4/4

x=-1

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