(x-1)(x+12)=17x

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Solution for (x-1)(x+12)=17x equation:



(x-1)(x+12)=17x
We move all terms to the left:
(x-1)(x+12)-(17x)=0
We add all the numbers together, and all the variables
-17x+(x-1)(x+12)=0
We multiply parentheses ..
(+x^2+12x-1x-12)-17x=0
We get rid of parentheses
x^2+12x-1x-17x-12=0
We add all the numbers together, and all the variables
x^2-6x-12=0
a = 1; b = -6; c = -12;
Δ = b2-4ac
Δ = -62-4·1·(-12)
Δ = 84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{84}=\sqrt{4*21}=\sqrt{4}*\sqrt{21}=2\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{21}}{2*1}=\frac{6-2\sqrt{21}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{21}}{2*1}=\frac{6+2\sqrt{21}}{2} $

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