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(x-1)(x+2)=6x
We move all terms to the left:
(x-1)(x+2)-(6x)=0
We add all the numbers together, and all the variables
-6x+(x-1)(x+2)=0
We multiply parentheses ..
(+x^2+2x-1x-2)-6x=0
We get rid of parentheses
x^2+2x-1x-6x-2=0
We add all the numbers together, and all the variables
x^2-5x-2=0
a = 1; b = -5; c = -2;
Δ = b2-4ac
Δ = -52-4·1·(-2)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{33}}{2*1}=\frac{5-\sqrt{33}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{33}}{2*1}=\frac{5+\sqrt{33}}{2} $
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