(x-1)(x+3)=(x-5)(x-4)

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Solution for (x-1)(x+3)=(x-5)(x-4) equation: 



(x-1)(x+3)=(x-5)(x-4)

We move all terms to the left:

(x-1)(x+3)-((x-5)(x-4))=0

We multiply parentheses ..

(+x^2+3x-1x-3)-((x-5)(x-4))=0



We calculate terms in parentheses: -((x-5)(x-4)), so:

(x-5)(x-4)

We multiply parentheses ..

(+x^2-4x-5x+20)

We get rid of parentheses

x^2-4x-5x+20

We add all the numbers together, and all the variables

x^2-9x+20

Back to the equation:

-(x^2-9x+20)



We get rid of parentheses

x^2-x^2+3x-1x+9x-3-20=0

We add all the numbers together, and all the variables

11x-23=0

We move all terms containing x to the left, all other terms to the right

11x=23

x=23/11

x=2+1/11

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