(x-1)(x+3+3/x-1)=(4-x/x-1)(x-1)

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Solution for (x-1)(x+3+3/x-1)=(4-x/x-1)(x-1) equation: 



(x-1)(x+3+3/x-1)=(4-x/x-1)(x-1)

We move all terms to the left:

(x-1)(x+3+3/x-1)-((4-x/x-1)(x-1))=0



Domain of the equation: x-1)!=0

x∈R





Domain of the equation: x-1)(x-1))!=0

x∈R



We add all the numbers together, and all the variables

(x-1)(x+3/x+2)-((-x/x+3)(x-1))=0

We multiply parentheses ..

(+x^2+3x^2+2x-1x-3x-2)-((-x/x+3)(x-1))=0

We multiply all the terms by the denominator


((+x^2+3x^2+2x-1x-3x-2))*x+3)(x-x-1))-((=0

We add all the numbers together, and all the variables

((+x^2+3x^2+2x-1x-3x-2))*x+3)(-1))-((=0

We add all the numbers together, and all the variables

((+x^2+3x^2+2x-1x-3x-2))*x=0

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