(x-1)(x+4)=(x+13)(x-4)

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Solution for (x-1)(x+4)=(x+13)(x-4) equation: 



(x-1)(x+4)=(x+13)(x-4)

We move all terms to the left:

(x-1)(x+4)-((x+13)(x-4))=0

We multiply parentheses ..

(+x^2+4x-1x-4)-((x+13)(x-4))=0



We calculate terms in parentheses: -((x+13)(x-4)), so:

(x+13)(x-4)

We multiply parentheses ..

(+x^2-4x+13x-52)

We get rid of parentheses

x^2-4x+13x-52

We add all the numbers together, and all the variables

x^2+9x-52

Back to the equation:

-(x^2+9x-52)



We get rid of parentheses

x^2-x^2+4x-1x-9x-4+52=0

We add all the numbers together, and all the variables

-6x+48=0

We move all terms containing x to the left, all other terms to the right

-6x=-48

x=-48/-6

x=+8

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