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(x-1)(x+5)=x2+4x-2.
We move all terms to the left:
(x-1)(x+5)-(x2+4x-2.)=0
We add all the numbers together, and all the variables
-(+x^2+4x-2.)+(x-1)(x+5)=0
We get rid of parentheses
-x^2-4x+(x-1)(x+5)+2.=0
We multiply parentheses ..
-x^2+(+x^2+5x-1x-5)-4x+2.=0
We add all the numbers together, and all the variables
-1x^2+(+x^2+5x-1x-5)-4x+2=0
We get rid of parentheses
-1x^2+x^2+5x-1x-4x-5+2=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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