(x-1)(x+7)=1

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Solution for (x-1)(x+7)=1 equation:



(x-1)(x+7)=1
We move all terms to the left:
(x-1)(x+7)-(1)=0
We multiply parentheses ..
(+x^2+7x-1x-7)-1=0
We get rid of parentheses
x^2+7x-1x-7-1=0
We add all the numbers together, and all the variables
x^2+6x-8=0
a = 1; b = 6; c = -8;
Δ = b2-4ac
Δ = 62-4·1·(-8)
Δ = 68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{68}=\sqrt{4*17}=\sqrt{4}*\sqrt{17}=2\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{17}}{2*1}=\frac{-6-2\sqrt{17}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{17}}{2*1}=\frac{-6+2\sqrt{17}}{2} $

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