(x-1)(x-1)(x-1)=(x-1)(x-1)

Solution for (x-1)(x-1)(x-1)=(x-1)(x-1) equation:

(x-1)(x-1)(x-1)=(x-1)(x-1)

We move all terms to the left:

(x-1)(x-1)(x-1)-((x-1)(x-1))=0

We multiply parentheses ..

(+x^2-1x-1x+1)(x-1)-((+x^2-1x-1x+1))=0


We calculate terms in parentheses: -((+x^2-1x-1x+1)), so:

(+x^2-1x-1x+1)

We get rid of parentheses

x^2-1x-1x+1

We add all the numbers together, and all the variables

x^2-2x+1

Back to the equation:

-(x^2-2x+1)


We get rid of parentheses

(+x^2-1x-1x+1)(x-1)-x^2+2x-1=0

We add all the numbers together, and all the variables

-1x^2+(+x^2-1x-1x+1)(x-1)+2x-1=0

We move all terms containing x to the left, all other terms to the right

-1x^2+(+x^2-1x-1x+1)(x-1)+2x=1