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(x-1)(x-1)+(x+2)(x+2)=0
We multiply parentheses ..
(+x^2-1x-1x+1)+(x+2)(x+2)=0
We get rid of parentheses
x^2-1x-1x+(x+2)(x+2)+1=0
We multiply parentheses ..
x^2+(+x^2+2x+2x+4)-1x-1x+1=0
We add all the numbers together, and all the variables
x^2+(+x^2+2x+2x+4)-2x+1=0
We get rid of parentheses
x^2+x^2+2x+2x-2x+4+1=0
We add all the numbers together, and all the variables
2x^2+2x+5=0
a = 2; b = 2; c = +5;
Δ = b2-4ac
Δ = 22-4·2·5
Δ = -36
Delta is less than zero, so there is no solution for the equation
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