(x-1)(x-1)-(x+3)(x+3)=2

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Solution for (x-1)(x-1)-(x+3)(x+3)=2 equation: 



(x-1)(x-1)-(x+3)(x+3)=2

We move all terms to the left:

(x-1)(x-1)-(x+3)(x+3)-(2)=0

We multiply parentheses ..

(+x^2-1x-1x+1)-(x+3)(x+3)-2=0

We get rid of parentheses

x^2-1x-1x-(x+3)(x+3)+1-2=0

We multiply parentheses ..

x^2-(+x^2+3x+3x+9)-1x-1x+1-2=0

We add all the numbers together, and all the variables

x^2-(+x^2+3x+3x+9)-2x-1=0

We get rid of parentheses

x^2-x^2-3x-3x-2x-9-1=0

We add all the numbers together, and all the variables

-8x-10=0

We move all terms containing x to the left, all other terms to the right

-8x=10

x=10/-8

x=-1+1/4

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