(x-1)(x-1)=(2x+1)(x+1)-(x+3)(x+3)

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Solution for (x-1)(x-1)=(2x+1)(x+1)-(x+3)(x+3) equation: 



(x-1)(x-1)=(2x+1)(x+1)-(x+3)(x+3)

We move all terms to the left:

(x-1)(x-1)-((2x+1)(x+1)-(x+3)(x+3))=0

We multiply parentheses ..

(+x^2-1x-1x+1)-((2x+1)(x+1)-(x+3)(x+3))=0



We calculate terms in parentheses: -((2x+1)(x+1)-(x+3)(x+3)), so:

(2x+1)(x+1)-(x+3)(x+3)

We multiply parentheses ..

(+2x^2+2x+x+1)-(x+3)(x+3)

We get rid of parentheses

2x^2+2x+x-(x+3)(x+3)+1

We multiply parentheses ..

2x^2-(+x^2+3x+3x+9)+2x+x+1

We add all the numbers together, and all the variables

2x^2-(+x^2+3x+3x+9)+3x+1

We get rid of parentheses

2x^2-x^2-3x-3x+3x-9+1

We add all the numbers together, and all the variables

x^2-3x-8

Back to the equation:

-(x^2-3x-8)



We get rid of parentheses

x^2-x^2-1x-1x+3x+1+8=0

We add all the numbers together, and all the variables

x+9=0

We move all terms containing x to the left, all other terms to the right

x=-9

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