(x-1)(x-2)(x+3)(x+4)+24=0

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Solution for (x-1)(x-2)(x+3)(x+4)+24=0 equation:



(x-1)(x-2)(x+3)(x+4)+24=0
We multiply parentheses ..
(+x^2-2x-1x+2)(x+3)(x+4)+24=0
We multiply parentheses ..
(+x^2-2x-1x+2)(+x^2+4x+3x+12)+24=0
We move all terms containing x to the left, all other terms to the right
(+x^2-2x-1x+2)(+x^2+4x+3x+12)=-24

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