(x-1)(x-2)(x-3)=(x+1)(x+2)

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Solution for (x-1)(x-2)(x-3)=(x+1)(x+2) equation: 



(x-1)(x-2)(x-3)=(x+1)(x+2)

We move all terms to the left:

(x-1)(x-2)(x-3)-((x+1)(x+2))=0

We multiply parentheses ..

(+x^2-2x-1x+2)(x-3)-((x+1)(x+2))=0



We calculate terms in parentheses: -((x+1)(x+2)), so:

(x+1)(x+2)

We multiply parentheses ..

(+x^2+2x+x+2)

We get rid of parentheses

x^2+2x+x+2

We add all the numbers together, and all the variables

x^2+3x+2

Back to the equation:

-(x^2+3x+2)



We get rid of parentheses

(+x^2-2x-1x+2)(x-3)-x^2-3x-2=0

We add all the numbers together, and all the variables

-1x^2+(+x^2-2x-1x+2)(x-3)-3x-2=0

We move all terms containing x to the left, all other terms to the right

-1x^2+(+x^2-2x-1x+2)(x-3)-3x=2

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