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(x-1)(x-2)(x-4)(x-8)=4x^2
We move all terms to the left:
(x-1)(x-2)(x-4)(x-8)-(4x^2)=0
determiningTheFunctionDomain -4x^2+(x-1)(x-2)(x-4)(x-8)=0
We multiply parentheses ..
-4x^2+(+x^2-2x-1x+2)(x-4)(x-8)=0
We multiply parentheses ..
-4x^2+(+x^2-2x-1x+2)(+x^2-8x-4x+32)=0
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