(x-1)(x-2)(x-4)(x-8)=4xxx

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Solution for (x-1)(x-2)(x-4)(x-8)=4xxx equation: 



(x-1)(x-2)(x-4)(x-8)=4xxx

We move all terms to the left:

(x-1)(x-2)(x-4)(x-8)-(4xxx)=0

We multiply parentheses ..

(+x^2-2x-1x+2)(x-4)(x-8)-4xxx=0

We multiply parentheses ..

(+x^2-2x-1x+2)(+x^2-8x-4x+32)-4xxx=0

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