(x-1)(x-2)+(x-1)(x-3=2(x-2)(x-3)

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Solution for (x-1)(x-2)+(x-1)(x-3=2(x-2)(x-3) equation: 



(x-1)(x-2)+(x-1)(x-3=2(x-2)(x-3)

We move all terms to the left:

(x-1)(x-2)+(x-1)(x-3-(2(x-2)(x-3))=0

We multiply parentheses ..

(+x^2-2x-1x+2)+(x-1)(x-3-(2(x-2)(x-3))=0



We calculate terms in parentheses: +(x-1)(x-3-(2(x-2)(x-3)), so:

x-1)(x-3-(2(x-2)(x-3)

determiningTheFunctionDomain
x-1)(x-(2(x-2)(x-3)-3

We multiply parentheses ..

-(2(+x^2-3x-2x+6)-3+x-1)(x

Back to the equation:

+(-(2(+x^2-3x-2x+6)-3+x-1)(x)



We get rid of parentheses

x^2+(-(2(+x^2-3x-2x+6)-3+x-1)x-2x-1x+2=0

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