(x-1)(x-2)-(x+2)(x+1)-3=0

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Solution for (x-1)(x-2)-(x+2)(x+1)-3=0 equation:



(x-1)(x-2)-(x+2)(x+1)-3=0
We multiply parentheses ..
(+x^2-2x-1x+2)-(x+2)(x+1)-3=0
We get rid of parentheses
x^2-2x-1x-(x+2)(x+1)+2-3=0
We multiply parentheses ..
x^2-(+x^2+x+2x+2)-2x-1x+2-3=0
We add all the numbers together, and all the variables
x^2-(+x^2+x+2x+2)-3x-1=0
We get rid of parentheses
x^2-x^2-x-2x-3x-2-1=0
We add all the numbers together, and all the variables
-6x-3=0
We move all terms containing x to the left, all other terms to the right
-6x=3
x=3/-6
x=-1/2

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