(x-1)(x-3)(x+2)(x-6)+18=0

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Solution for (x-1)(x-3)(x+2)(x-6)+18=0 equation: 



(x-1)(x-3)(x+2)(x-6)+18=0

We multiply parentheses ..

(+x^2-3x-1x+3)(x+2)(x-6)+18=0

We multiply parentheses ..

(+x^2-3x-1x+3)(+x^2-6x+2x-12)+18=0

We move all terms containing x to the left, all other terms to the right

(+x^2-3x-1x+3)(+x^2-6x+2x-12)=-18

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