(x-1)(x-3)+12=0

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Solution for (x-1)(x-3)+12=0 equation: 



(x-1)(x-3)+12=0

We multiply parentheses ..

(+x^2-3x-1x+3)+12=0

We get rid of parentheses

x^2-3x-1x+3+12=0

We add all the numbers together, and all the variables

x^2-4x+15=0

a = 1; b = -4; c = +15;
Δ = b2-4ac
Δ = -42-4·1·15
Δ = -44
Delta is less than zero, so there is no solution for the equation

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