(x-1)(x-3)=(x+5)(x-4)

Solution for (x-1)(x-3)=(x+5)(x-4) equation:

(x-1)(x-3)=(x+5)(x-4)

We move all terms to the left:

(x-1)(x-3)-((x+5)(x-4))=0

We multiply parentheses ..

(+x^2-3x-1x+3)-((x+5)(x-4))=0


We calculate terms in parentheses: -((x+5)(x-4)), so:

(x+5)(x-4)

We multiply parentheses ..

(+x^2-4x+5x-20)

We get rid of parentheses

x^2-4x+5x-20

We add all the numbers together, and all the variables

x^2+x-20

Back to the equation:

-(x^2+x-20)


We get rid of parentheses

x^2-x^2-3x-1x-x+3+20=0

We add all the numbers together, and all the variables

-5x+23=0

We move all terms containing x to the left, all other terms to the right

-5x=-23

x=-23/-5

x=4+3/5