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(x-1)(x-1.05)=0
We multiply parentheses ..
(+x^2-1.05x-1x+1.05)=0
We get rid of parentheses
x^2-1.05x-1x+1.05=0
We add all the numbers together, and all the variables
x^2-2.05x+1.05=0
a = 1; b = -2.05; c = +1.05;
Δ = b2-4ac
Δ = -2.052-4·1·1.05
Δ = 0.0025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.05)-\sqrt{0.0025}}{2*1}=\frac{2.05-\sqrt{0.0025}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.05)+\sqrt{0.0025}}{2*1}=\frac{2.05+\sqrt{0.0025}}{2} $
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