(x-1)*2+3(x+4)=2x-(x-2)

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Solution for (x-1)*2+3(x+4)=2x-(x-2) equation: 



(x-1)*2+3(x+4)=2x-(x-2)

We move all terms to the left:

(x-1)*2+3(x+4)-(2x-(x-2))=0

We multiply parentheses

2x+3x-(2x-(x-2))-2+12=0



We calculate terms in parentheses: -(2x-(x-2)), so:

2x-(x-2)

We get rid of parentheses

2x-x+2

We add all the numbers together, and all the variables

x+2

Back to the equation:

-(x+2)



We add all the numbers together, and all the variables

5x-(x+2)+10=0

We get rid of parentheses

5x-x-2+10=0

We add all the numbers together, and all the variables

4x+8=0

We move all terms containing x to the left, all other terms to the right

4x=-8

x=-8/4

x=-2

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