(x-1)*2+3(x+4)=2x-(x-2)

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Solution for (x-1)*2+3(x+4)=2x-(x-2) equation:



(x-1)*2+3(x+4)=2x-(x-2)
We move all terms to the left:
(x-1)*2+3(x+4)-(2x-(x-2))=0
We multiply parentheses
2x+3x-(2x-(x-2))-2+12=0
We calculate terms in parentheses: -(2x-(x-2)), so:
2x-(x-2)
We get rid of parentheses
2x-x+2
We add all the numbers together, and all the variables
x+2
Back to the equation:
-(x+2)
We add all the numbers together, and all the variables
5x-(x+2)+10=0
We get rid of parentheses
5x-x-2+10=0
We add all the numbers together, and all the variables
4x+8=0
We move all terms containing x to the left, all other terms to the right
4x=-8
x=-8/4
x=-2

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