(x-1)+(2x-1)=3(x+2)-4

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Solution for (x-1)+(2x-1)=3(x+2)-4 equation: 



(x-1)+(2x-1)=3(x+2)-4

We move all terms to the left:

(x-1)+(2x-1)-(3(x+2)-4)=0

We get rid of parentheses

x+2x-(3(x+2)-4)-1-1=0



We calculate terms in parentheses: -(3(x+2)-4), so:

3(x+2)-4

We multiply parentheses

3x+6-4

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We add all the numbers together, and all the variables

3x-(3x+2)-2=0

We get rid of parentheses

3x-3x-2-2=0

We add all the numbers together, and all the variables

-4!=0

There is no solution for this equation

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