(x-1)+(x-2)+(x-3)+(x-4)=10

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Solution for (x-1)+(x-2)+(x-3)+(x-4)=10 equation: 



(x-1)+(x-2)+(x-3)+(x-4)=10

We move all terms to the left:

(x-1)+(x-2)+(x-3)+(x-4)-(10)=0

We get rid of parentheses

x+x+x+x-1-2-3-4-10=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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