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(x-1)+2x=2(x+2)
We move all terms to the left:
(x-1)+2x-(2(x+2))=0
We add all the numbers together, and all the variables
2x+(x-1)-(2(x+2))=0
We get rid of parentheses
2x+x-(2(x+2))-1=0
We calculate terms in parentheses: -(2(x+2)), so:We add all the numbers together, and all the variables
2(x+2)
We multiply parentheses
2x+4
Back to the equation:
-(2x+4)
3x-(2x+4)-1=0
We get rid of parentheses
3x-2x-4-1=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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