(x-1)+8=1-3(x+2)

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Solution for (x-1)+8=1-3(x+2) equation: 



(x-1)+8=1-3(x+2)

We move all terms to the left:

(x-1)+8-(1-3(x+2))=0

We get rid of parentheses

x-(1-3(x+2))-1+8=0



We calculate terms in parentheses: -(1-3(x+2)), so:

1-3(x+2)

determiningTheFunctionDomain
-3(x+2)+1

We multiply parentheses

-3x-6+1

We add all the numbers together, and all the variables

-3x-5

Back to the equation:

-(-3x-5)



We add all the numbers together, and all the variables

x-(-3x-5)+7=0

We get rid of parentheses

x+3x+5+7=0

We add all the numbers together, and all the variables

4x+12=0

We move all terms containing x to the left, all other terms to the right

4x=-12

x=-12/4

x=-3

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