(x-1)/(3x)+8x=(x+2)/(x)

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Solution for (x-1)/(3x)+8x=(x+2)/(x) equation: 



(x-1)/(3x)+8x=(x+2)/(x)

We move all terms to the left:

(x-1)/(3x)+8x-((x+2)/(x))=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

8x+(x-1)/3x-((x+2)/x)=0

We calculate fractions


8x+(x-1)*x)/3x^2+(-((x+2)*3x)/3x^2=0

We calculate fractions


8x+((x-1)*x)*3x^2)/(3x^2+(*3x^2)+(-((x+2)*3x)*3x^2)/(3x^2+(*3x^2)=0



We calculate terms in parentheses: +(-((x+2)*3x)*3x^2)/(3x^2+(*3x^2), so:

-((x+2)*3x)*3x^2)/(3x^2+(*3x^2

We multiply all the terms by the denominator


-((x+2)*3x)*3x^2)+((*3x^2)*(3x^2

Back to the equation:

+(-((x+2)*3x)*3x^2)+((*3x^2)*(3x^2)



We get rid of parentheses

8x+((x-1)*x)*3x^2)/(3x^2+*3x^2+(-((x+2)*3x)*3x^2)+((*3x^2)*3x^2=0

We multiply all the terms by the denominator


8x*(3x^2+((x-1)*x)*3x^2)+(*3x^2)*(3x^2+((-((x+2)*3x)*3x^2))*(3x^2+(((*3x^2)*3x^2)*(3x^2=0

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