(x-1)/(x+1)-(x+2)/(x-2)=3

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Solution for (x-1)/(x+1)-(x+2)/(x-2)=3 equation: 



(x-1)/(x+1)-(x+2)/(x-2)=3

We move all terms to the left:

(x-1)/(x+1)-(x+2)/(x-2)-(3)=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (x-2)!=0

We move all terms containing x to the left, all other terms to the right

x!=2

x∈R



We calculate fractions


((x-1)*(x-2))/((x+1)*(x-2))+(-(x+2)*(x+1))/((x+1)*(x-2))-3=0



We calculate terms in parentheses: +((x-1)*(x-2))/((x+1)*(x-2)), so:

(x-1)*(x-2))/((x+1)*(x-2)

We multiply all the terms by the denominator


(x-1)*(x-2))

Back to the equation:

+((x-1)*(x-2)))





We calculate terms in parentheses: +(-(x+2)*(x+1))/((x+1)*(x-2)), so:

-(x+2)*(x+1))/((x+1)*(x-2)

We multiply all the terms by the denominator


-(x+2)*(x+1))

Back to the equation:

+(-(x+2)*(x+1)))

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