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D( x )
x-5 = 0
x-5 = 0
x-5 = 0
x-5 = 0 // + 5
x = 5
x in (-oo:5) U (5:+oo)
(x-1)/(x-5) = 4/(x-5) // - 4/(x-5)
(x-1)/(x-5)-(4/(x-5)) = 0
(x-1)/(x-5)-4*(x-5)^-1 = 0
(x-1)/(x-5)-4/(x-5) = 0
x-4-1 = 0
x-5 = 0
(x-5)/(x-5) = 0
(x-5)/(x-5) = 0 // * x-5
x-5 = 0
x-5 = 0 // + 5
x = 5
x in { 5}
x belongs to the empty set
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