(x-1)/2+(x+3)/4=(x-1)2+3

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Solution for (x-1)/2+(x+3)/4=(x-1)2+3 equation: 


x in (-oo:+oo)

(x-1)/2+(x+3)/4 = (x-1)^2+3 // - (x-1)^2+3

(x-1)/2+(x+3)/4-(x-1)^2-3 = 0

(x-1)/2+(x+3)/4-1*(x-1)^2-3 = 0

(4*(x-1))/(2*4)+(2*(x+3))/(2*4)+(-1*2*4*(x-1)^2)/(2*4)+(-3*2*4)/(2*4) = 0

4*(x-1)+2*(x+3)-1*2*4*(x-1)^2-3*2*4 = 0

6*x-8*x^2+16*x-24-8+2 = 0

22*x-8*x^2-24-6 = 0

22*x-8*x^2-30 = 0

22*x-8*x^2-30 = 0

2*(11*x-4*x^2-15) = 0

11*x-4*x^2-15 = 0

DELTA = 11^2-(-15*(-4)*4)

DELTA = -119

DELTA < 0

2 = 0

2/(2*4) = 0

2/(2*4) = 0 // * 2*4

2 = 0

x belongs to the empty set

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